Math, asked by k9alpanarakshagargb, 1 year ago

If p=-2,q=-1,r=3 then p3+q3+r3+3pqr=?

Answers

Answered by ThePhoenix
0

(-2 × 3) + (-1 × 3) + (3 × 3) + [3 × (-2) × (-1) × 3]

= -6 + -3 + 9 + 18

= -9 + 27

= 18

Answered by Anonymous
1

Hopes it will help you...

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