if p^2+q^2=25 and pq=12 find the value 2 (p+q)^2+3 (p-q)^2
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Answered by
0
p² + q² = 25
pq = 12
p² + q² = (p - q)² + 2pq
25=(p-q)² + 2 x 12
1 = (p - q)²
also
p²+q² = (p+q)² - 2pq
25=(p+q)² - 2x12
25+ 24 = (p+q)²
(p + q)² = 49
2(p+q)² + 3(p-q)²
= 2 x 49 + 3x1
= 98 + 3
= 101
Answered by
1
Answer:
101
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