Physics, asked by NathanKumar1315, 1 year ago

If p = 2 x square y upon zthe percentage error in x y z are 1% 2% and 3% respectively if percentage error in P is n% the value of n is

Answers

Answered by arpitasahani
6

Pls mark my ans as BRAINLIEST ..

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Answered by rishkrith123
0

Answer:

The value of n is 7.

Explanation:

Given,

p = 2x²y/z

The percentage error in x is x/Δx(100)1%.

The percentage error in y is y/Δy(100) 2%.

The percentage error in z is z/Δz(100) 3%.

The percentage error in p is p/Δp(100) n%.

To find,

The value of 'n'.

Calculation,

p = 2x²y/z

percentage error in p = 2 × percentage error in x + percentage error in y + percentage error in z.

p/Δp (100) = 2 × x/Δx (100) + y/Δy (100) + z/Δz (100)

⇒ n% = 2 (1%) + 2% + 3%

⇒ n% = 7%

⇒ n = 7

Therefore, the value of n is 7.

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