Question

if P=2m²+5n²-6, Q=m²-6n²+8 and R=3n²+4m²+2.Find 2P+Q+3R​

Answer 1

Step-by-step explanation:

=2p+Q+3R

=2(2m²+5n²-6)+m²-6n²+8+3(3n²+4m²+2)

=4m²+10n²-12+m²-6n²+8+9n²+12m²+6

=4m²+m²+12m²+10n²-6n²+9n²-12+8+6

=17m²+13n²+2

Answer 2

Answer:

2P+Q+3R=17m^2+13n^2+2

Step-by-step explanation:

P=2m^2+5n^2-6

Q=m^2-6n^2+8

R=3n^2+4m^2+2

2P+Q+3R

=2(2m^2+5n^2-6)+(m^2-6n^2+8)+

3(3n^2+4m^2+2)

=4m^2+10n^2-12+m^2-6n^2+8+9n^2+12m^2+6

=4m^2+m^2+12m^2+10n^2-6n^2+9n^2-12+8+6

=17m^2+13n^2+2