Question

If (p,2p+1) is the solution of the linear equation 4x+3y=23. Find the value of p

Answer 1

The given equation is

4x+3y=23

Since (p, 2p+1) is a solution to this equation, It should satisfy the equation.

Therefore,

4(p)+3(2p+1)=23

4p+6p+3=23

10p=23-3=20

p=20/10

=> p=2

Answer 2

The value of p is 2 ,if (p,2p+1) is the solution of the linear equation 4x+3y=23.

Given:

• A point (p, 2p+1)
• A linear equation 4x+3y=23.

To find:

• Find the value of p.

Solution:

Concept to be used:

If P(r,s) is a point and it is lies on the linear equation ax+by+c=0, then the point P satisfies the equation.

i.e. ar+bs+c=0

Step 1:

As point is (p, 2p+1).

Value of x= p

y= 2p+1

Step 2:

Put values of x and y in the equation.

$4(p) + 3(2p + 1) = 23$

or

$4p + 6p + 3 = 23$

or

$10p = 23 - 3$

or

$10p = \: 20$

or

$p = \frac{20}{10}$

or

$\bf p = 2$

Thus,

Value of p is 2.

If (p,2p+1) is the solution of the linear equation 4x+3y=23.

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