Math, asked by lakojichandrarao470, 11 months ago

If P = 2y square - 5 - 2y , Q = y square - 3y + 6 and R = y square - 4y + 2, find P + 2Q + 2R

Answers

Answered by RahatNaaz
5

Step-by-step explanation:

p = 2y {}^{2}  - 5 - 2y \\ q = y {}^{2} - 3y + 6 \\ r = y {}^{2} - 4y + 2 \\ p + 2q + 2r = (2y {}^{2}  - 5 - 2y) + 2(y {}^{2}  - 3y + 6) + 2(y {}^{2}  - 4y + 2) \\  = 2y {}^{2}  - 5 - 2y + 2y {}^{2}  - 6y + 12 + 2y {}^{2}  - 8y + 4 \\  = 6y {}^{2}  - 16y + 11

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