Question

if P=2y²+4xy+4,
Q=-3y²-3xy+7,
R=5y²-3xy+8
find P+Q-R​

Answer 1

Answer:

(2y²+4xy+4) + (3y²-3xy+7) - (5y²-3xy+8)

→ 2y²+4xy+4 +3y²-3xy+7 -5y²+3xy-8

→ 2y² +3y²-5y² +4xy-3xy+3xy +4+7-8

→ +5y²-5y² +4xy +3

→ 4xy +3

is your answer

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Answer 2

Answer:

P+Q-R= -6y²+4xy+3

Step-by-step explanation:

(2y²+4xy+4)+(-3y²-3xy+7)-(5y²-3xy+8)

=2y²+4xy+4-3y²-3xy+7-5y²+3xy-8

=2y²-3y²-5y²+4xy-3xy+3xy+4+7-8

= -6y²+4xy+3

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