Question

If P = 2y2 - 5 - 2y, Q = y2 - 3y + 6 and R
Find the perimeter of the given triangle
3 - 3y + 6 and R=12 - 4y + 2. find P +20 +2R.
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Answer 1

Answer:

here, p = 2y ^ 2 - 5 - 2y q = y ^ 2 - 3y + 6 r = y ^ 2 - 4y + 2

now;

p+2q +2r = (2y² -5 -2y) + 2(y² -3y +6) + 2(y² -4y +2)

= 2y² -5 -2y +2y² -6y +12 + 2y² -8y +4

= 6y² -16y +11 answer

hope it helps :)