Question

If P(3.4) and Q7, 7) are two points and PR = 10, where P, Q and R are collinear, then R​

Answer 1

Answer:

R ( 11 , 10 )

Step-by-step explanation:

Given:

P = ( 3, 4 ) and Q = ( 7, 7 )

Let R ( x, y )

Let us first find out the distance between P and Q

PQ = √ (y2 – y1 )² + (x2 – x1)²

PQ = √ (7 – 4 )² + ( 7 – 3 )²

PQ = √ 9 + 16

PQ = √ 25

PQ = 5 units

But it is given that PR = 10 units

Therefore Point P lies first then Q and then R

distance QR = 10 – 5 = 5 units

Since PQ = QR = 5 units

Hence Q is the mid point of PR

using mid point formula

7 = ( 3 + x ) /2

14 = 3 + x

11 = x

and

7 = ( 4 + y ) / 2

14 = 4 + y

10 = y

Hence point R is ( 11, 10 )

Answer 2

this is the answer of the question

f

just

just

lj

and if so