Question

If p=3,b=5 then 2Sin-cos =

Answer 1

Answer:

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Step-by-step explanation:

secθ=

5

13

secθ=

B

H

=

5

13

Using Pythagoras Theorem,

H

2

=P

2

+B

2

13

2

=P

2

+5

2

P

2

=144

P=12

Now,

4sinθ−9cosθ

2sinθ−3cosθ

=

4(

13

12

)−9(

13

5

)

2(

13

12

)−3(

13

5

)

=

13

48−45

13

24−15

= 3