If (p+3) is d hcf of 81 and 108...find d value of p...
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6
P+3=d
Hcf of 81 and 108 =d
Hcf =d=27
P+3=37
P=24
Hcf of 81 and 108 =d
Hcf =d=27
P+3=37
P=24
Answered by
3
HCF of 81&108=d
d=27
we know
p+3=d
therefore p+3=27
p=24(since 27-3=24)
d=27
we know
p+3=d
therefore p+3=27
p=24(since 27-3=24)
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