If p=-3,q=0,r=2,find the value of 2pq+3qr -4pr
Answers
Answered by
13
Answer:
2pq+3qr-4pr
2(-3)(0)+3(0)(2)-4(-3)(2)
2(0)+3(0)-4(-6)
0+0+24
24
Answered by
3
Answer:
24
Step-by-step explanation:
2pq+3qr-4pr
p=-3
q=0
r=2
therefore,
[2×(-3)×0] + [3×0×2] - [4×(-3)×2]
0+0-(-24)
24
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