Question

IF p=3 q=1 r=0 a=5 b=-1 find the value of
a. 3p-2q+4r
b. -4q-3a+2b
c. -4p +5a-a
d. pq-3qb-br
e2qb-ra+4r2
f.p2-2q2+3b2
g-p2-bp+3b2
h.ap-ab-ba​

Answer 1

hey buddy,

here is your ans..

$a) \: 3(3) - 2(1) + 4(0) = 9 - 2 + 0 = 7 \\ b) - 4(1) - 3(5) + 2( - 1) = - 21 \\ c) - 4(3) + 5(5) - 5 = 12 + 25 - 5 = 32 \\ d)3(1) - 3(3)( - 1) - ( -1)(0) = 12$

I did 4 parts

I hope it helps you

and other 4 parts will be easy for you

thank you

have a great Evening

Answer 2

Answer:

a. 7

b.-21

c.8

d.6

e. -6

f. 14

g. -3

h.25

Step-by-step explanation:

a. 3p-2q+4r

=3×3 -2×1+4×0

= 9-2

=7

b. -4q-3a+2b

= -4×1 -3×5 +2×(-1)

= -4-15-2

=-21

c. -4p+5a-a

= -4p +4a

= -4×3+4×5

= -12+20

= 8

d. pq -3qb-br

= 3×1 -3×1×(-1) -(-1)×0

= 3 +3

= 6

e. 2qb-ra+4r^2

=2 × 3×(-1) -0×5 + 4×(0)^2

= -6

f. p^2+2q^2+3b^2

= 3^2 + 2 ×(1)^2 +3 (-1)^2

= 9 +2+3

= 14

g. -p^2-bp+3b^2

= -(3)^2 - (-1)×3 +3×(-1)^2

= -9+3+3

=-3

h. ap- ab -ba

= ap- 2ab

= 5×3-2×5×(-1)

=15+10

=25