Math, asked by poulomisa1, 1 year ago

If p=-3,q=-1,r=3 then 3p2q+5pq2+ 2pqr

Answers

Answered by shashriksingh
0
3p×2q+5pq×2+2×p×q×r
= 3×(-3)×2×(-1)+5×(-3)×(-1)×2+2×(-3)×(-1)×3
= -9×(-2)-15×(-2)+(-6)×(-3)
= 18+30+18
= 66
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