Question

if p= -3,q=-1and r=2,find the value of 3p²q²r²-2pqr+7
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Answer 1

Answer:

22

is the answer of this question

Answer 2

★ Concept :-

• While solving algebraic expressions, Make sure that variables are at left side.

• Variables are the alphabets which are used in a algebraic expression.

• Constants are the numbers with are used in algebraic expressions$.$

Answer :-

• 3p²q²r²-2pqr+7 = 127.

Given :-

• p = -3,
• q = -1
• r = 2

To find :-

• Find the value of 3p²q²r²-2pqr+7?

Solution :-

➜ 3p²q²r²-2pqr+7

➜ 3(-3)²(-1)²(2)² - 2(-3×1×2) + 7

➜ 3(9)(1)(4) - 2(-6) + 7

➜ 108 + 12 + 7

➜ 108 + 19

➜ 127

Hence, The value of 3p²q²r²-2pqr+7 = 127.

Know more :-

Follow these , While solving any algebraic expressions.

• ( + ) × ( − ) = ( − )
• ( + ) × ( + ) = ( + )
• ( - ) × ( + ) = ( - )
• ( - ) × ( - ) = ( + )