Question

if p=3 q=1r=0 b=-1 a=5 find the value of

(a) 2pb -ra +4r2^​

Answer 1

Solution:

Given :

• P = 3
• q = 1
• r = 0
• b = -1
• a = 5

So, we have to find the value of given Equation;

Note: Substitute given value in Equation:

Equation : 2pb - ra + 4r2^q

☞ 2.3.-1 - 0.-1 + 4.0.2¹

☞ -6 + 0 + 0

☞ - 6

Therefore, Value of 2pb - ra + 4r2^q is -6.

Answer 2

Solution:

Correction : Correct Equation-

2pb - ra + 4r2^q

Given that :

• P = 3
• q = 1
• r = 0
• b = -1
• a = 5

Given Equation : 2pb - ra + 4r2^q

= 2.3.-1 - 0.- +4.0.2^1

= -6 + 0 + 0

= - 6 +0

= -6

Therefore, Value of given Equation is -6.