Math, asked by aratrika7987, 1 year ago

If p=3,q=-5 & r=4,then find the value of p²+q²+r²-pq-qr-pr explain it..​

Answers

Answered by nprashan0019
4

Answer:

P=3 q=-5 and r=4

So, (3)^2+(-5)^2+(4)^2-(3*-5)-(-5*4)-(3*4)

Therefor, 9+25+16-(-15)-(-20)-(12)

Hence, 50+15+20-12

So the answer is 73

Answered by karan152672
4

Answer:

3×3 +(-5×-5)+(4×4)-(3×-5)-(-5×4)-(3×4)

9+25+16+15+20-12

73

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