If p=3,q=-5 & r=4,then find the value of p²+q²+r²-pq-qr-pr explain it..
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Answered by
4
Answer:
P=3 q=-5 and r=4
So, (3)^2+(-5)^2+(4)^2-(3*-5)-(-5*4)-(3*4)
Therefor, 9+25+16-(-15)-(-20)-(12)
Hence, 50+15+20-12
So the answer is 73
Answered by
4
Answer:
3×3 +(-5×-5)+(4×4)-(3×-5)-(-5×4)-(3×4)
9+25+16+15+20-12
73
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