Math, asked by rajskrraj49, 9 hours ago

If p = 3 sec²θ and q = 3tan²θ – 1,
then find p – q.​

Answers

Answered by hemanthjayavarapu110
0

Answer:

answer is 4

I am thinking it's right

Attachments:
Answered by tennetiraj86
2

Step-by-step explanation:

Given:-

p = 3 sec^2 θ and q = 3tan^2 θ – 1

To find:-

Find the value of p - q ?

Solution:-

Given that

p = 3 sec^2 θ

q = 3tan^2 θ – 1

Now , The value of p-q

=> (3 sec^2 θ ) - (3tan^2 θ – 1)

=> 3 sec^2 θ - 3 tan^2 θ + 1

=>3 ( sec^2 θ - tan^2 θ) + 1

We know that

Sec^2 A - Tan^2 A = 1

=> 3(1) + 1

=> 3 + 1

=> 4

p - q = 4

Answer:-

The value of p - q for the given problem is 4

Used formula:-

  • Sec^2 A - Tan^2 A = 1
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