Question

if P =3i+4j+2k, its direction cosines are​

Answer 1

Answer:

Given = P =3i+4j+2k

to find = direction cosines

solution =

1st find the magnitude of vctor P

|P| =  √3² + √4²+ √2²

|P|=√29

for direction cosins be ,

cos∝= p.i / |P| = 3/√29

cosβ =p.j/|P| = 4 / √29

cosΥ=  p.k/|P|/√29

direction cosines

3/√29, 4/√29 , 2/√29