Question

if p = 3x + 1 , q=1/3 (9x + 13) and p : q = 6 : 5 the find x​

Answer 1

Answer:

Value of x will be minus 7...

Step-by-step explanation:

PLEASE REFER TO THE ABOVE ATTACHMENT

... MARK AS BRAINLIEST IF YOU LIKED MY ANSWER. .

Answer 2

$\bf{\large{\underline{\underline{Answer:-}}}}$

x = - 7

$\bf{\large{\underline{\underline{Explanation:-}}}}$

Given :- p = 3x + 1, q = 1/3(9x + 13)

p : q = 6 : 5

To find : Value of x

Solution :-

Given that p = 3x + 1, q = 1/3( 9x + 13)

First simplify q = 1/3(9x + 13)

$\dfrac{1}{3}(9x + 13)$

$= \dfrac{1}{3}(9x) + \dfrac{1}{3}(13)$

$= 1(3x) + \dfrac{13}{3}$

$= 3x + \dfrac{13}{3}$

So, q = 3x + 13/3

Given that, p : q = 6 : 5

According to the question :

$\dfrac{p}{q} = \dfrac{6}{5}$

We know that p = 3x + 1, q = 3x + 13/3

We know that p = 3x + 1, q = 3x + 13/3By substituting the values in the above equation,

$\dfrac{3x + 1}{3x + \frac{13}{3} } = \dfrac{6}{5}$

By Cross multiplication :

$(3x + 1)5 = 6(3x + \dfrac{13}{3})$

$3x(5) + 1(5) = 6(3x) + 6( \dfrac{13}{3})$

$15x + 5 = 18x + 2(13)$

$15x + 5 = 18x + 26$

$15x - 18x = 26 - 5$

$- 3x = 21$

$x = \dfrac{21}{ - 3}$

$x = - \dfrac{21}{3}$

$x = - 7$

$\Huge{\boxed{\sf{x = -7}}}$

$\bf{\large{\underline{\underline{Verification:-}}}}$

$\dfrac{3( - 7) + 1}{3( - 7) + \frac{13}{3} } = \dfrac{6}{5}$

$\dfrac{ - 21 + 1}{ - 21 + \frac{13}{3} } = \dfrac{6}{5}$

$\dfrac{ - 20}{ \frac{ - 21(3)}{1(3)} + \frac{13}{3} } = \dfrac{6}{5}$

$\dfrac{ - 20}{ \frac{ - 63}{3} + \frac{13}{3} } = \dfrac{6}{5}$

$\dfrac{ - 20}{\frac{ - 63 + 13}{3} } = \dfrac{6}{5}$

$\dfrac{ - 20}{ - \frac{50}{3} } = \dfrac{6}{5}$

$- 20( - \dfrac{3}{50}) = \dfrac{6}{5}$

$- 2( - \dfrac{3}{5}) = \dfrac{6}{5}$

$\dfrac{6}{5} = \dfrac{6}{5}$