Math, asked by braingamer10, 1 year ago

if p = 3x + 1 , q=1/3 (9x + 13) and p : q = 6 : 5 the find x​

Answers

Answered by satyam2804
19

Answer:

Value of x will be minus 7...

Step-by-step explanation:

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Answered by Anonymous
38

\bf{\large{\underline{\underline{Answer:-}}}}

x = - 7

\bf{\large{\underline{\underline{Explanation:-}}}}

Given :- p = 3x + 1, q = 1/3(9x + 13)

p : q = 6 : 5

To find : Value of x

Solution :-

Given that p = 3x + 1, q = 1/3( 9x + 13)

First simplify q = 1/3(9x + 13)

 \dfrac{1}{3}(9x + 13)

 =  \dfrac{1}{3}(9x) +  \dfrac{1}{3}(13)

 = 1(3x) +  \dfrac{13}{3}

 = 3x +  \dfrac{13}{3}

So, q = 3x + 13/3

Given that, p : q = 6 : 5

According to the question :

 \dfrac{p}{q} =  \dfrac{6}{5}

We know that p = 3x + 1, q = 3x + 13/3

We know that p = 3x + 1, q = 3x + 13/3By substituting the values in the above equation,

 \dfrac{3x + 1}{3x +  \frac{13}{3} }  =  \dfrac{6}{5}

By Cross multiplication :

(3x + 1)5 = 6(3x +  \dfrac{13}{3})

3x(5) + 1(5) = 6(3x) + 6( \dfrac{13}{3})

15x + 5 = 18x + 2(13)

15x + 5 = 18x + 26

15x - 18x = 26 - 5

 - 3x = 21

x =  \dfrac{21}{ - 3}

x =  -  \dfrac{21}{3}

x = - 7

\Huge{\boxed{\sf{x = -7}}}

\bf{\large{\underline{\underline{Verification:-}}}}

 \dfrac{3( - 7) + 1}{3( - 7) +  \frac{13}{3} } =  \dfrac{6}{5}

 \dfrac{ - 21 + 1}{ - 21 +  \frac{13}{3} } = \dfrac{6}{5}

 \dfrac{ - 20}{ \frac{ - 21(3)}{1(3)} +  \frac{13}{3} } =  \dfrac{6}{5}

 \dfrac{ - 20}{ \frac{ - 63}{3} +  \frac{13}{3}  } =  \dfrac{6}{5}

 \dfrac{ - 20}{\frac{ - 63 + 13}{3} }  =  \dfrac{6}{5}

 \dfrac{ - 20}{ -  \frac{50}{3} } =  \dfrac{6}{5}

 - 20( -  \dfrac{3}{50}) =  \dfrac{6}{5}

 - 2( -  \dfrac{3}{5}) =  \dfrac{6}{5}

 \dfrac{6}{5} =  \dfrac{6}{5}


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