Question

If p(×)=3x^2-4×+5.
Find p(0),p(1),p(-1)?​

Answer 1

$p(0) = 3(0) {}^{2} - 4(0) + 5 \\ = 0 - 0 + 5 \\ p(0) = 5 \\ \\ p(1) = 3(1) {}^{2} - 4(1) + 5 \\ = 3 - 4 + 5 \\ p(1) = 4 \\ \\ p( - 1) = 3( - 1) {}^{2} - 4( - 1) + 5 \\ = - 3 + 4 + 5 \\ p( - 1) = 6$

Hope it helps you!!!