Question

if P=3x²+3x+6,Q=9x²-7x-5 and R=-3x²+7x+8 find (P-Q+R)​

Answer 1

Answer:

$-3x^2+17x+19$

Step-by-step explanation:

$P=3x^2+3x+6\\Q=9x^2-7x-5\\R=3x^2+7x+8\\Now\\P-Q+R\\(3x^2+3x+6)-(9x^2-7x-5)+(3x^2+7x+8)\\(3-9+3)x^2+(3+7+7)x+(6+5+8)\\-3x^2+17x+19$

Answer 2

Step-by-step explanation:

P-Q+R.

P-Q=P=3x²+3x+6-(9x²-7x-5)

=3x²+3x+6-9x²+7x+5

P+Q=-6x²+10x+11

P-Q+R=-6x²+10x+11-3x²+7x+8

-9x²+17x+19.