if P(4,2),Q(14,5)andR(6,4)are the vertices of triangle PQR, find area of triangle PQR
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P(4,2) x1,y1
Q(14,5) x2,y2
R(6,4) x3,y3
area of triangle =
1/2 | x1(y2-y3) + x2(y3-y1) + x(3y1-y2) |
1/2 | 4(5-4) + 14(4-2) + 6(2-5) |
1/2 | 4 + 28 - 18|
1/2 | 14 |
1/2 x 14
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