Question

If P= ₹4,200 , R=12% , T= 2years. Find the total amount to be in : a) Simple interest. b) compound interest. c) difference in amount of simple interest and compound interest​

Answer 1

Answer:

add it =₹ 48903 and 7 years

Answer 2

Step-by-step explanation:

$i)simple \: interest = \frac{prt}{100}$

$\frac{(4200)(12)(2)}{100} = \frac{100800}{100} = 1008$

$compound \: interest = a = p {(1 + \frac{r}{100} )}^{n}$

ii) where P=rs.4200

R =12%

T (n)=2years

$amount = 4200 {(1 + \frac{12}{100} )}^{2}$

$= 4200( { \frac{112}{100} )}^{2}$

$4200 { (\frac{28}{25}) }^{2}$

$4200( \frac{ {28}^{2} }{ {25}^{2} } )$

$4200 \times \frac{784}{625}$

simplify 4200 and 625

$168 \times \frac{784}{25}$

$\frac{168 \times784 }{25}$

$\frac{131712}{25} = 5268.48$

$amount = 5268.48$

$ci = a - p$

$= 5268.48 - 4200 = 1068.48$

$compount \: interest = rs.1068.48$

c)

$amt.in \: si \: - amt \: in \: ci$

$amt.in \: si \: = principle+ intrest$

$amt. = 4200 + 1008 = 5208$

$diff. = 5268.48 - 5208$

$= 60.48$

hope it's helpful...