Question

If P(4,6)and q (8,-10) and A is
midpoint of seg pq, find the
co-ordinates
of point A​

Answer 1

Answer:

A = ( (4+8)÷2), (6-10)÷2)

A = (6, -2)

Answer 2

Step-by-step explanation:

P(4,6) and Q(8,-10)

Since A is the midpoint of line segment PQ

So Coordinates of P are $x_{1} = 4 & y_{1} = 6$

Coordinates of Q are $x_{2} = 8 y_{2} = -10$

Let Coordinates of A are $(x,y)$

So ,

$x= \frac{x_{1}+x_{2} }{2} \\x= \frac{4+8}{2}\\x=6$

$y=\frac{y_{1}+y_{2} }{2}\\y=\frac{6-10}{2}\\y=-2$

So Co-ordinates of A are (6,-2)  Answer