IF p=4, q=3 and r=2, find the value of: p³+q³-r³-3pqr.
please answer
Answers
Answered by
1
Answer: 11
Step-by-step explanation:
p³+q³-r³-3pqr
= 4^3 +3^3 - 2^3 -3*4*3*2
= 64 + 27 -8 - 72
= 91- 80
= 11
Answered by
1
Answer:
p=4
q=3
r=2
p^3+q^3-r^3-3pqr
=(4)^3+(3)^3-(2)^3-3.4.3.2
=64+27-8-72
=91-80
=11
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