Question

if p=4,q=3,andr= -2,then find the value of the algebraic expression
p²+q²-r²
------------
pq+qr-pr​

Answer 1

Answer:

substituting p=4,q=3,r=-2, in p²+q²-r² gives

4²+3²-(-2)²

=16+9-4

=25-4

=21

also,pq+qr-pr=(4×3)+(3×(-2))-(4×(-2))

=12+(-6)-(-8)

=12-6+8

=14

Then p²+q²-r²÷pq+qr-pr

=21/14

=3/2 also equal to 1.5

So,answer:3/2 that is also=1.5

Hope helps you..