Question

If p=4 , Q=6,R=10 , S=20 ,T =22 then find the value of p×Q-p​

Answer 1

Answer:

$\huge\pink{Answer}$

Given expression is,

p 3

q 3

r 3

3pqr

Put the value of

p=

4, q=

−3

,

r=

2

, we get

p 3

q 3

r 3

3pqr

= (4)

3

+ (−3)

3

− (2)

3

− 3× 4× −3× 2

= 64− 27− 8+ 72

= 136+ −35= 101

Answer 2

To find : value of  $P\times Q -P$

Given :  $P = 4 , Q = 6 , R = 10 , S = 20 , T =22$

Solution :

• As per given data we are given that $P = 4 , Q = 6 , R = 10 , S = 20 , T =22$ . Using these value we have to find the value of $P\times Q -P$ .

• Therefore , by substituting the given values and following BODMAS rule we find the answer .
• $P\times Q -P$

        $= 4\times 6 -4 \\= 24 - 4 \\= 20$

Hence, value of $P\times Q -P$ is $20$ .