If p=5-2√6 find p^2-1/p^2
Answers
Answered by
17
P =5-2√6
p^2 = (5-2√6)^2
Using Identity (a-b)^2 = a^2+b^2 -2ab
(5-2√6)^2
=25+24-20√6
=49-20√6
p^2-1
=49-20√6-1
=48-20√6
p^2-1/p^2
=48-20√6/49-20√6
By rationalizing the denominator
=48-20√6(49+20√6) / 49-20√6(49+20√6)
=2352 - 960√6 -980√6 -2400/49^2 - 20√6^2
= -48-1940√6 /2401 - 2400
=-48-1940√6
p^2 = (5-2√6)^2
Using Identity (a-b)^2 = a^2+b^2 -2ab
(5-2√6)^2
=25+24-20√6
=49-20√6
p^2-1
=49-20√6-1
=48-20√6
p^2-1/p^2
=48-20√6/49-20√6
By rationalizing the denominator
=48-20√6(49+20√6) / 49-20√6(49+20√6)
=2352 - 960√6 -980√6 -2400/49^2 - 20√6^2
= -48-1940√6 /2401 - 2400
=-48-1940√6
amulnandhini757:
How the 48 is come
Answered by
21
I think the question must be to find p^2 + 1/p^2
If p = 5-2√6
then 1/p = 1/5-2√6
= 5+2√6 (When you rationalise the denominator)
p*1/p = 1
p+1/p = 5-2√6+(5+2√6)
= 10
(p+1/p)^2 = 10^2
p^2 +1/p^2 +2(p*1/p) =100
p^2 +1/p^2 +2 = 100
p^2 +1/p^2 = 100-2
= 98
If p = 5-2√6
then 1/p = 1/5-2√6
= 5+2√6 (When you rationalise the denominator)
p*1/p = 1
p+1/p = 5-2√6+(5+2√6)
= 10
(p+1/p)^2 = 10^2
p^2 +1/p^2 +2(p*1/p) =100
p^2 +1/p^2 +2 = 100
p^2 +1/p^2 = 100-2
= 98
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