Question

if p ( -5, -3) , Q ( -4,-6) , R( 2, -3) and S ( 1,2) are the vertices of a quadrilateral PQRS find its are?​

Answer 1

Answer:

use the area formula

Step-by-step explanation:

we can use the area formula in it..

area of triangle pqr in parallelogram pqrsis

$\frac{1}{2} |( - 5)(6 + 3) + ( - 4)( - 3 + 3) + (2)( - 3 - 6)|$

$\frac{1}{2} | - 45 + 0 - 18|$

$\frac{1}{2} | - 63|$

$= \frac{63}{2}$

now area of another triangle prs=

$\frac{1}{2} |( - 5)( - 3 - 2) + (2)(2 + 3) + (1)( - 3 - 2)|$

$\frac{1}{2} |25 + 10 - 5|$

$\frac{1}{2} |35 - 5|$

$\frac{1}{2} |30|$

= 15

therefore area of quad pqrs

$= \frac{63}{2} + 15$

by taking lcm

ans is 46.5 sq units