If P(5,-4) Q(8,5) and R(2,-1) are the vertices of triangle PQR , M is midpoint of QR and A is a point on PM jointed such that PA /AM= 2/1 find the coordinate of A
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Let Q and R be the base vertices and P be the vertex at the apex. First find the midpoint of the Q & R as the median from apex joins the midpoint of base line. Midpoint of QR is (5/2,-3/2). Now, Let us find the slope between the midpoint of these Two and P i.e., 11. Put it in the slope equation formula y-y1 = slope × (x-x1). (x1,y1) can be Vertex P or Midpoint of QR. equation comes to be 11x-y-29=0.
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Answer:
5,0
Step-by-step explanation:
m is mid point of qr
therefore, m=8+2/2, 5-1/2
m=5,2
a is a point on m such that pa/am=1/2
therefore,
a=mx2+nx1/m+n, my2+ny1/m+n
a=10+5/3, 4-4/3
therefore, a =5,0
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