If P(5, 7), Q(x, -2) and R (-3, y) are collinear points such that PQ = 1/2 PR, calculate the values of x and y.
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5
Answer:
x =1 and y =11
Step-by-step explanation:
Given
PQ=1/2PR
point Q is the mid point of PQ
(x,-2) = (5-3 /2 , 7-y /2)
x = 5-3 /2
x = 2 / 2
x = 1
-2 = 7-y / 2
7-y= -4
-y = -11
y = 11
so...
x =1 and y =11
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