IF P=5 and G=5 and 0 = 30° find
magnitude
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As the particle has no acceleration in horizontal direction, thus its velocity component in horizontal direction remains the same all the time whereas its vertical component changes.
Using v
y
=u
y
+gt
Magnitude of change in vertical component of velocity ΔV
y
=gt=9.8×10=98m/s
∴ Change in momentum Δp=mΔV
y
⟹ Δp=(0.5)(98)=49 kg.m/s
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