Question

if p = -5, prove that x^3 + 15px+p^3 - 125=0

Answer 1

value of p= -5
given equation=x^3+15px+p^3-125=0
putting value of p in given equation
x^3+15(-5)x+(-5)^3-125=0
x^3-75x+125-125=0
x^3-75x=0
x(x^2-75)=0
x=0         X^2-75=0
               X^2=75
               X=root 75
               X=5 root 3
therefore value of X is 0 OR 5 root 3

Answer 2

Answer:

Value of p= -5

given equation=x^3+15px+p^3-125=0

putting value of p in given equation

x^3+15(-5)x+(-5)^3-125=0

x^3-75x+125-125=0

x^3-75x=0

x(x^2-75)=0

x=0         X^2-75=0

               X^2=75

               X=root 75

               X=5 root 3

therefore value of X is 0 OR 5 root 3

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