Question

If p = 5x^3+3x^2-4x+1 , Q = 3x^3+5x^2+3x-8 and R = 6x^3-4x^2-7x+3 , find ( P+Q ) - R .​

Answer 1

Step-by-step explanation:

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Answer 2

We have

• To find out (P + Q) - R

Given,

• P = 5x³ + 3x² - 4x + 1
• Q = 3x³ + 5x² + 3x - 8
• R = 6x³ - 4x² - 7x + 3

Here,

$\small \rm{}P + Q = {5x}^{3} + {3x}^{2} - 4x + 1 + ( {3x}^{3} + {5x}^{2} + 3x - 8) \\ \small \rm{ \to {5x}^{3} + {3x}^{3} + {3x}^{2} + {5x}^{2} - 4x + 3x + 1 - 8 } \\ \small \rm{\to \orange{{8x}^{3} + {8x}^{2} - x - 7 }}$

Now,

$\huge \bf{(P + Q) - R} \\ \\ \rm \to {8x}^{3} + {8x}^{2} - x - 7 - ( {6x}^{3} - {4x}^{2} - 7x + 3 ) \\ \rm \to {8x}^{3} + {8x}^{2} - x - 7 - {6x}^{3} + {4x}^{2} + 7x - 3 \\ \rm \to {8x}^{3} - {6x}^{3} + {8x}^{2} + {4x}^{2} - x + 7x - 7 - 3 \\ \to \rm \red{{2x}^{3} + {12x}^{2} + 6x - 10}$

Hence,

• Required Value = 2x³ + 12x² + 6x - 10