Question

if p=6,q=2,r=3 , find p/3+q/2-r

Answer 1

Answer:

6/3+2/2-3 = 2+1-3 = 3-3=0.

Step-by-step explanation:

First of all substitute the values now in the first no 6÷3 gives us 2 ,second no.2÷2 gives us 1, Third no. itself is 0.

Ans is 2+1-3

= 3-3=0

So the value is 0.

Hope it helps.