Question

if p=6 q=7 then find the value of 7q^2-6q^2+2pq

Answer 1

7q^2-6q^2+2pq
= 7 (7)^2-6(7)^2+ 2*6*7
= 7*49-6*49+84
=343-294+84
= 333

Answer 2

Answer:

Required value is 42.

Step-by-step explanation:

Given term is

$7 {q}^{2} - 6 {q}^{2} + 2pq$

We want to find value of the given term when p = 6 and q = 7.

We are putting value of p and q in $7 {q}^{2} - 6 {q}^{2} + 2pq$ and get

$7 \times {6}^{2} - 6 \times {7}^{2} + 2 \times 6 \times 7 \\ = 7 \times 36 - 6 \times 49 + 84 \\ = 252 - 294 + 84 \\ = 42$

This is a problem of value putting part of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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