Question

If p,6,q,r,12 are in AP .Find the value of p,q,r​

Answer 1

Step-by-step explanation:

Coordinate of point P,Q and R are P(6,-1),Q(1,3) and R(x,8)

Given, PQ=QR

So by distance formula we have,

Distance between two points =

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

PQ=

(6−1)

2

+(−1−3)

2

=

25+14

=

41

∴PQ

2

=41=QR

2

but, QR

2

=(x−1)

2

+25

41=x

2

+1−2x+25

⇒41=x

2

+1−2x+25

⇒x

2

−2x+26=41

⇒x

2

−2x−15=0

⇒x

2

−5x+3x−15=0

⇒x(x−5)+3(x−5)=0

⇒(x+3)(x−5)=0

⇒x=−3,5

Answer 2

Answer:

1234:563=369%06=580-260 /646(876) 675:0987