If p = – 7 and q = 12 and x2 + px + q = 0, then the value of ‘x’ is
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Step-by-step explanation:
x^2-7x+12=0
x^2-4x-3x+12=0
x(x-4)-3(x-4)=0
(x-4)(x-3)=0
x=4,3
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