Question

If P = 7x² + 5xy − 9y²

, Q = 4y² − 3x²− 6xy and R = −4x2
² + xy + 5y²

, show that

P + Q + R = 0.​

Answer 1

Answer:

$p + q + r = 0 \\ 7 {x}^{2} + 5xy + - 9 {y}^{2} + 4 {y}^{2} - 3 {x}^{2} - 6xy - 4 {x + }^{2} + xy + 5 {y}^{2} = 0$

Answer 2

Step-by-step explanation:

P = 7x² + 5xy − 9y²

Q = 4y² − 3x²− 6xy

R = −4x² + xy + 5y²

P+Q+R

• (7x² + 5xy − 9y²)+( 4y² − 3x²− 6xy)+(−4x² + xy + 5y²)
• 7x²-3x²-4x²+5xy-6xy+xy-9y²+4y²+5y²
• 0+0+0
• 0 ({ proved })