Question

if p=9 then 3√p(p^2+3p+3)+1​

Answer 1

Answer:

1000

Step-by-step explanation:

3√p(p² +3p + 3) + 1​

= 3√9 (9² + 3×9 +3) + 1

= ​3×3 (81 + 27 + 3) + 1

= (9 × 111) + 1

= 999 + 1

= 1000

Answer 2

3√p(p^2+3p+3)+1

= 3√9(9^2+3*9+3)+1

= 3*3(81+27+3)+1

= 9 * 111 + 1

= 999 + 1

= 1000 ⬅️ ANS.