Question

If p=99 then 3√p(p²+3p+3)+1

Answer 1

Step-by-step explanation:

$\sqrt[3]({p }^{3} + 3 p {}^{2} + 3p + 1)$

$\sqrt[3]{(p + 1) {}^{3} }$

= P + 1

= 99 + 1

= 100.