If P(A) = 0.2 ,P(B) = 0.7 and P(AUB) = 0.1 then P(A∩ B) =
Answers
Answered by
0
Step-by-step explanation:
p(A) = 0.2
p(B) = 0.7
p(A U B) = 0.1
p(A n B) = ?
p(A U B) = p(A) + p(B) - p(A n B)
0.1 = 0.2 + 0.7 - x
therefore, x = 0.8. (here x = p (A n B)
Answered by
1
Answer:
P(A∩ B) = 0.8
Step-by-step explanation:
By addition rules in probability ans statistics we know that:-
P(AUB) = P(A) + P(B) - P(A∩ B)
We may write this formula like this-
P(A∩ B) = P(A) + P(B) - P(AUB)
After putting the value of P(A), P(B) and P(AUB)
P(A∩ B) = 0.2 + 0.7 - 0.1 = 0.9 - 0.1 = 0.8
Hence the answer is - P(A∩ B) = 0.8
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