If P(A) = 0.3, P(B) = 0.2 and P(C) = 0.1 and A,B,C are independent events, find the
probability of occurrence of at least one of the three events A, B and C.
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Answer:
probability is 0.2
because rhe probability of getting any one is
0.3+0.2+0.1/3
=0.6/3
=0.2
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