Question

If P(A) = 0.3, P(B) = 0.2 and P(C) = 0.1 and A,B,C are independent events, find the probability of occurrence of at least one of the three events A , B and C

Answer 1

1/3 is the probability of one of them

Answer 2

Concept

Probability is a mathematical branch is about the numerical interpretations of how likely an event is, or how likely it is that the proposal will be true. The probability of an event is a number between 0 and 1, where, as we speak, 0 indicates the impossibility of the event and 1 indicates certainty.

Given

P(A) = 0.3, P(B) = 0.2 and P(C) = 0.1 and events A,B,C are independent events

FIND

The probability of occurrence of at least one of he three events A , B and C

Solution

• Given total three events A,B and C so total outcome will be 3
• we have to find probability of occurrence of at least one of the three events so favorable outcome will be 1
• Probability= favorable outcome/total outcome
• Probability= 1/3=0.34

So the probability of occurrence of at least one of he three events A , B and C will be 0.34

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