Math, asked by jaysingh1361, 2 months ago

If P(A) =0.37, P(B)=0.42, P(AUB)=0.7 then P(A intersection B) =

Answers

Answered by Anonymous
9

Given :

P(A) = 0.37

P(B) = 0.42

P(AUB) = 0.7

P(AᑎB) =?

P(AUB) = P(A) +P(B) - P(AᑎB)

0.7 = 0.37 + 0.42 - P(AᑎB)

0.7 = 0.79 - P(AᑎB)

P(AᑎB) = 0.79-0.7

P(AᑎB) = 0.09

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