If P(A)=0.4, P(B)=0.8 and P(B/A)=0.6, then find P(A'/B)??
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P(A)=0.4 => P(A') = 1 - P(A) = 0.6
P(B) = 0.8 => P(B') = 0.2
P(B/A) = 0.6 => P(B'/A) = 1 - P(B/A) = 0.4
P(A Π B) = P(A AND B) = P(B/A) * P(A) = 0.24
A' Π B = A' intersection with B = (U - A) Π B = B - A Π B
P(A' Π B) = P(B) - P(A Π B) = 0.56
P(A' / B) = P(A' Π B) / P(B) = 0.56 /0.8 = 0.7
P(B) = 0.8 => P(B') = 0.2
P(B/A) = 0.6 => P(B'/A) = 1 - P(B/A) = 0.4
P(A Π B) = P(A AND B) = P(B/A) * P(A) = 0.24
A' Π B = A' intersection with B = (U - A) Π B = B - A Π B
P(A' Π B) = P(B) - P(A Π B) = 0.56
P(A' / B) = P(A' Π B) / P(B) = 0.56 /0.8 = 0.7
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