Question

if P(A) = 0.51,P(B) = 0.43,P(AnB) = 0.16 and P( Neither A nor B )​

Answer 1

Answer:

0.22

Step-by-step explanation:

P(AUB)'= P(neither A nor B)

hence,P(neither A nor B)=1-P(AUB)

p(AUB)=P(A)+P(B)-P(AnB)

=0.51+0.43-.016

=0.78

P(neither A nor B)=1-P(AUB)

=1-0.78

=0.22