If P(A) = 0.60, P(B) = 0.58, and P(A υ B) = 0.70, then P(A ∩ B) is:
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Answer:
P(A) = 0.60 , P(B) = 0.58, and P(A υ B) = 0.70
P(A υ B) = P(A) + P(B) - P ( A ∩ B )
P ( A ∩ B ) = P(A) + P(B) - P(A υ B)
= 0.60 + 0.58 - 0.70
= 0.48 ( answer )
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Answered by
0
Answer:
P(A∩B)=0.48
Step-by-step explanation:
Given: P(A) = 0.60, P(B) = 0.58, and P(A υ B) = 0.70.
To find the value of P(A ∩ B).
We know that: P(A U B)=P(A)+P(B)-P(A∩B) ...(1)
Substituting values P(A) = 0.60, P(B) = 0.58, and P(A U B) = 0.70 in equation (1) we get:
P(A U B)=P(A)+P(B)-P(A∩B)
0.70=0.60+0.58-P(A∩B)
0.70-0.60-0.58= - P(A∩B)
0.48= P(A∩B)
Therefore, the value of P(A∩B)=0.48.
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