Math, asked by AyushKrishnan4673, 2 months ago

If P(A)=0.62, P(A union B)=0.72, and P(A intersection B)=0.66, then P(B)=

Answers

Answered by MaheswariS
2

\textbf{Given:}

\mathsf{P(A)=0.62}

\mathsf{P(A\,\cup\,B)=0.72}

\mathsf{P(A\,\cap\,B)=0.66}

\textbf{To find:}

\mathsf{P(B)}

\textbf{Solution:}

\textbf{Addition theorem of probability:}

\textsf{Let A and B be any two events}

\mathsf{Then,}\;\boxed{\mathsf{P(A\,\cup\,B)=P(A)+P(B)-P(A\,\cap\,B)}}

\mathsf{Consider,}

\mathsf{P(A\,\cup\,B)=P(A)+P(B)-P(A\,\cap\,B)}

\mathsf{0.72=0.62+P(B)-0.66}

\mathsf{0.72-0.62+0.66=P(B)}

\mathsf{0.10+0.66=P(B)}

\implies\boxed{\mathsf{P(B)=0.76}}

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